simply pass a filename to a command?
simply pass a filename to a command?
Whats the easiest way to pass the file name and path to a program?- file changes, move file to someplace else so it wont trigger again.pass that path to a program or batch for processing.as in-path1/pic.jpgmove(or rename) to path2/pic.jpgjpegoptim path2/pic.jpgetc.having it all happen in the GUI would be best.passing arguments to a batch would also work.I just hadn't been able to figure out how to do it with robotask.
simply pass a filename to a command?
You can easily determine the name of file in the File loop (for example)
Next, you need to move file to another folder.
Your task will looks so:
File loop //and save current file name to C_FileName variable (for example)
move {c_FileName} to c:\path2
end loop
If you need to know new full file name do concatenation the ne path and original file name.
There is {ExtractFileName()} variable in order to extract file name fron full path of the file.
Just use
c:\path2\{ExtractFileName({c_FileName})}
Also see other system variables: menu Options | Variables
Next, you need to move file to another folder.
Your task will looks so:
File loop //and save current file name to C_FileName variable (for example)
move {c_FileName} to c:\path2
end loop
If you need to know new full file name do concatenation the ne path and original file name.
There is {ExtractFileName()} variable in order to extract file name fron full path of the file.
Just use
c:\path2\{ExtractFileName({c_FileName})}
Also see other system variables: menu Options | Variables
simply pass a filename to a command?
Thus your task will be such:
File loop //and save current file name to C_FileName variable (for example)
move {c_FileName} to c:\path2
run program jpegoptim c:\path2\{ExtractFileName({c_FileName})}
end loop
File loop //and save current file name to C_FileName variable (for example)
move {c_FileName} to c:\path2
run program jpegoptim c:\path2\{ExtractFileName({c_FileName})}
end loop